3.1.57 \(\int \frac {1}{(a+b \sin (c+d x))^{7/2}} \, dx\) [57]

3.1.57.1 Optimal result
3.1.57.2 Mathematica [A] (verified)
3.1.57.3 Rubi [A] (verified)
3.1.57.4 Maple [A] (verified)
3.1.57.5 Fricas [C] (verification not implemented)
3.1.57.6 Sympy [F]
3.1.57.7 Maxima [F]
3.1.57.8 Giac [F]
3.1.57.9 Mupad [F(-1)]

3.1.57.1 Optimal result

Integrand size = 14, antiderivative size = 292 \[ \int \frac {1}{(a+b \sin (c+d x))^{7/2}} \, dx=\frac {2 b \cos (c+d x)}{5 \left (a^2-b^2\right ) d (a+b \sin (c+d x))^{5/2}}+\frac {16 a b \cos (c+d x)}{15 \left (a^2-b^2\right )^2 d (a+b \sin (c+d x))^{3/2}}+\frac {2 b \left (23 a^2+9 b^2\right ) \cos (c+d x)}{15 \left (a^2-b^2\right )^3 d \sqrt {a+b \sin (c+d x)}}+\frac {2 \left (23 a^2+9 b^2\right ) E\left (\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )|\frac {2 b}{a+b}\right ) \sqrt {a+b \sin (c+d x)}}{15 \left (a^2-b^2\right )^3 d \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}-\frac {16 a \operatorname {EllipticF}\left (\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right ),\frac {2 b}{a+b}\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}{15 \left (a^2-b^2\right )^2 d \sqrt {a+b \sin (c+d x)}} \]

output
2/5*b*cos(d*x+c)/(a^2-b^2)/d/(a+b*sin(d*x+c))^(5/2)+16/15*a*b*cos(d*x+c)/( 
a^2-b^2)^2/d/(a+b*sin(d*x+c))^(3/2)+2/15*b*(23*a^2+9*b^2)*cos(d*x+c)/(a^2- 
b^2)^3/d/(a+b*sin(d*x+c))^(1/2)-2/15*(23*a^2+9*b^2)*(sin(1/2*c+1/4*Pi+1/2* 
d*x)^2)^(1/2)/sin(1/2*c+1/4*Pi+1/2*d*x)*EllipticE(cos(1/2*c+1/4*Pi+1/2*d*x 
),2^(1/2)*(b/(a+b))^(1/2))*(a+b*sin(d*x+c))^(1/2)/(a^2-b^2)^3/d/((a+b*sin( 
d*x+c))/(a+b))^(1/2)+16/15*a*(sin(1/2*c+1/4*Pi+1/2*d*x)^2)^(1/2)/sin(1/2*c 
+1/4*Pi+1/2*d*x)*EllipticF(cos(1/2*c+1/4*Pi+1/2*d*x),2^(1/2)*(b/(a+b))^(1/ 
2))*((a+b*sin(d*x+c))/(a+b))^(1/2)/(a^2-b^2)^2/d/(a+b*sin(d*x+c))^(1/2)
 
3.1.57.2 Mathematica [A] (verified)

Time = 0.97 (sec) , antiderivative size = 198, normalized size of antiderivative = 0.68 \[ \int \frac {1}{(a+b \sin (c+d x))^{7/2}} \, dx=\frac {2 \left (-\frac {\left (\left (23 a^2+9 b^2\right ) E\left (\frac {1}{4} (-2 c+\pi -2 d x)|\frac {2 b}{a+b}\right )+8 a (-a+b) \operatorname {EllipticF}\left (\frac {1}{4} (-2 c+\pi -2 d x),\frac {2 b}{a+b}\right )\right ) \left (\frac {a+b \sin (c+d x)}{a+b}\right )^{5/2}}{(a-b)^3}+\frac {b \cos (c+d x) \left (34 a^4-5 a^2 b^2+3 b^4+2 a b \left (27 a^2+5 b^2\right ) \sin (c+d x)+b^2 \left (23 a^2+9 b^2\right ) \sin ^2(c+d x)\right )}{\left (a^2-b^2\right )^3}\right )}{15 d (a+b \sin (c+d x))^{5/2}} \]

input
Integrate[(a + b*Sin[c + d*x])^(-7/2),x]
 
output
(2*(-((((23*a^2 + 9*b^2)*EllipticE[(-2*c + Pi - 2*d*x)/4, (2*b)/(a + b)] + 
 8*a*(-a + b)*EllipticF[(-2*c + Pi - 2*d*x)/4, (2*b)/(a + b)])*((a + b*Sin 
[c + d*x])/(a + b))^(5/2))/(a - b)^3) + (b*Cos[c + d*x]*(34*a^4 - 5*a^2*b^ 
2 + 3*b^4 + 2*a*b*(27*a^2 + 5*b^2)*Sin[c + d*x] + b^2*(23*a^2 + 9*b^2)*Sin 
[c + d*x]^2))/(a^2 - b^2)^3))/(15*d*(a + b*Sin[c + d*x])^(5/2))
 
3.1.57.3 Rubi [A] (verified)

Time = 1.41 (sec) , antiderivative size = 318, normalized size of antiderivative = 1.09, number of steps used = 18, number of rules used = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.286, Rules used = {3042, 3143, 27, 3042, 3233, 27, 3042, 3233, 27, 3042, 3231, 3042, 3134, 3042, 3132, 3142, 3042, 3140}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {1}{(a+b \sin (c+d x))^{7/2}} \, dx\)

\(\Big \downarrow \) 3042

\(\displaystyle \int \frac {1}{(a+b \sin (c+d x))^{7/2}}dx\)

\(\Big \downarrow \) 3143

\(\displaystyle \frac {2 b \cos (c+d x)}{5 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{5/2}}-\frac {2 \int -\frac {5 a-3 b \sin (c+d x)}{2 (a+b \sin (c+d x))^{5/2}}dx}{5 \left (a^2-b^2\right )}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\int \frac {5 a-3 b \sin (c+d x)}{(a+b \sin (c+d x))^{5/2}}dx}{5 \left (a^2-b^2\right )}+\frac {2 b \cos (c+d x)}{5 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{5/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\int \frac {5 a-3 b \sin (c+d x)}{(a+b \sin (c+d x))^{5/2}}dx}{5 \left (a^2-b^2\right )}+\frac {2 b \cos (c+d x)}{5 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{5/2}}\)

\(\Big \downarrow \) 3233

\(\displaystyle \frac {\frac {16 a b \cos (c+d x)}{3 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{3/2}}-\frac {2 \int -\frac {3 \left (5 a^2+3 b^2\right )-8 a b \sin (c+d x)}{2 (a+b \sin (c+d x))^{3/2}}dx}{3 \left (a^2-b^2\right )}}{5 \left (a^2-b^2\right )}+\frac {2 b \cos (c+d x)}{5 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{5/2}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {\int \frac {3 \left (5 a^2+3 b^2\right )-8 a b \sin (c+d x)}{(a+b \sin (c+d x))^{3/2}}dx}{3 \left (a^2-b^2\right )}+\frac {16 a b \cos (c+d x)}{3 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{3/2}}}{5 \left (a^2-b^2\right )}+\frac {2 b \cos (c+d x)}{5 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{5/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\int \frac {3 \left (5 a^2+3 b^2\right )-8 a b \sin (c+d x)}{(a+b \sin (c+d x))^{3/2}}dx}{3 \left (a^2-b^2\right )}+\frac {16 a b \cos (c+d x)}{3 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{3/2}}}{5 \left (a^2-b^2\right )}+\frac {2 b \cos (c+d x)}{5 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{5/2}}\)

\(\Big \downarrow \) 3233

\(\displaystyle \frac {\frac {\frac {2 b \left (23 a^2+9 b^2\right ) \cos (c+d x)}{d \left (a^2-b^2\right ) \sqrt {a+b \sin (c+d x)}}-\frac {2 \int -\frac {a \left (15 a^2+17 b^2\right )+b \left (23 a^2+9 b^2\right ) \sin (c+d x)}{2 \sqrt {a+b \sin (c+d x)}}dx}{a^2-b^2}}{3 \left (a^2-b^2\right )}+\frac {16 a b \cos (c+d x)}{3 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{3/2}}}{5 \left (a^2-b^2\right )}+\frac {2 b \cos (c+d x)}{5 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{5/2}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\frac {\frac {\int \frac {a \left (15 a^2+17 b^2\right )+b \left (23 a^2+9 b^2\right ) \sin (c+d x)}{\sqrt {a+b \sin (c+d x)}}dx}{a^2-b^2}+\frac {2 b \left (23 a^2+9 b^2\right ) \cos (c+d x)}{d \left (a^2-b^2\right ) \sqrt {a+b \sin (c+d x)}}}{3 \left (a^2-b^2\right )}+\frac {16 a b \cos (c+d x)}{3 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{3/2}}}{5 \left (a^2-b^2\right )}+\frac {2 b \cos (c+d x)}{5 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{5/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {\int \frac {a \left (15 a^2+17 b^2\right )+b \left (23 a^2+9 b^2\right ) \sin (c+d x)}{\sqrt {a+b \sin (c+d x)}}dx}{a^2-b^2}+\frac {2 b \left (23 a^2+9 b^2\right ) \cos (c+d x)}{d \left (a^2-b^2\right ) \sqrt {a+b \sin (c+d x)}}}{3 \left (a^2-b^2\right )}+\frac {16 a b \cos (c+d x)}{3 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{3/2}}}{5 \left (a^2-b^2\right )}+\frac {2 b \cos (c+d x)}{5 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{5/2}}\)

\(\Big \downarrow \) 3231

\(\displaystyle \frac {\frac {\frac {\left (23 a^2+9 b^2\right ) \int \sqrt {a+b \sin (c+d x)}dx-8 a \left (a^2-b^2\right ) \int \frac {1}{\sqrt {a+b \sin (c+d x)}}dx}{a^2-b^2}+\frac {2 b \left (23 a^2+9 b^2\right ) \cos (c+d x)}{d \left (a^2-b^2\right ) \sqrt {a+b \sin (c+d x)}}}{3 \left (a^2-b^2\right )}+\frac {16 a b \cos (c+d x)}{3 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{3/2}}}{5 \left (a^2-b^2\right )}+\frac {2 b \cos (c+d x)}{5 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{5/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {\left (23 a^2+9 b^2\right ) \int \sqrt {a+b \sin (c+d x)}dx-8 a \left (a^2-b^2\right ) \int \frac {1}{\sqrt {a+b \sin (c+d x)}}dx}{a^2-b^2}+\frac {2 b \left (23 a^2+9 b^2\right ) \cos (c+d x)}{d \left (a^2-b^2\right ) \sqrt {a+b \sin (c+d x)}}}{3 \left (a^2-b^2\right )}+\frac {16 a b \cos (c+d x)}{3 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{3/2}}}{5 \left (a^2-b^2\right )}+\frac {2 b \cos (c+d x)}{5 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{5/2}}\)

\(\Big \downarrow \) 3134

\(\displaystyle \frac {\frac {\frac {\frac {\left (23 a^2+9 b^2\right ) \sqrt {a+b \sin (c+d x)} \int \sqrt {\frac {a}{a+b}+\frac {b \sin (c+d x)}{a+b}}dx}{\sqrt {\frac {a+b \sin (c+d x)}{a+b}}}-8 a \left (a^2-b^2\right ) \int \frac {1}{\sqrt {a+b \sin (c+d x)}}dx}{a^2-b^2}+\frac {2 b \left (23 a^2+9 b^2\right ) \cos (c+d x)}{d \left (a^2-b^2\right ) \sqrt {a+b \sin (c+d x)}}}{3 \left (a^2-b^2\right )}+\frac {16 a b \cos (c+d x)}{3 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{3/2}}}{5 \left (a^2-b^2\right )}+\frac {2 b \cos (c+d x)}{5 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{5/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {\frac {\left (23 a^2+9 b^2\right ) \sqrt {a+b \sin (c+d x)} \int \sqrt {\frac {a}{a+b}+\frac {b \sin (c+d x)}{a+b}}dx}{\sqrt {\frac {a+b \sin (c+d x)}{a+b}}}-8 a \left (a^2-b^2\right ) \int \frac {1}{\sqrt {a+b \sin (c+d x)}}dx}{a^2-b^2}+\frac {2 b \left (23 a^2+9 b^2\right ) \cos (c+d x)}{d \left (a^2-b^2\right ) \sqrt {a+b \sin (c+d x)}}}{3 \left (a^2-b^2\right )}+\frac {16 a b \cos (c+d x)}{3 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{3/2}}}{5 \left (a^2-b^2\right )}+\frac {2 b \cos (c+d x)}{5 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{5/2}}\)

\(\Big \downarrow \) 3132

\(\displaystyle \frac {\frac {\frac {\frac {2 \left (23 a^2+9 b^2\right ) \sqrt {a+b \sin (c+d x)} E\left (\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )|\frac {2 b}{a+b}\right )}{d \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}-8 a \left (a^2-b^2\right ) \int \frac {1}{\sqrt {a+b \sin (c+d x)}}dx}{a^2-b^2}+\frac {2 b \left (23 a^2+9 b^2\right ) \cos (c+d x)}{d \left (a^2-b^2\right ) \sqrt {a+b \sin (c+d x)}}}{3 \left (a^2-b^2\right )}+\frac {16 a b \cos (c+d x)}{3 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{3/2}}}{5 \left (a^2-b^2\right )}+\frac {2 b \cos (c+d x)}{5 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{5/2}}\)

\(\Big \downarrow \) 3142

\(\displaystyle \frac {\frac {\frac {\frac {2 \left (23 a^2+9 b^2\right ) \sqrt {a+b \sin (c+d x)} E\left (\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )|\frac {2 b}{a+b}\right )}{d \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}-\frac {8 a \left (a^2-b^2\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}} \int \frac {1}{\sqrt {\frac {a}{a+b}+\frac {b \sin (c+d x)}{a+b}}}dx}{\sqrt {a+b \sin (c+d x)}}}{a^2-b^2}+\frac {2 b \left (23 a^2+9 b^2\right ) \cos (c+d x)}{d \left (a^2-b^2\right ) \sqrt {a+b \sin (c+d x)}}}{3 \left (a^2-b^2\right )}+\frac {16 a b \cos (c+d x)}{3 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{3/2}}}{5 \left (a^2-b^2\right )}+\frac {2 b \cos (c+d x)}{5 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{5/2}}\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {\frac {\frac {\frac {2 \left (23 a^2+9 b^2\right ) \sqrt {a+b \sin (c+d x)} E\left (\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )|\frac {2 b}{a+b}\right )}{d \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}-\frac {8 a \left (a^2-b^2\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}} \int \frac {1}{\sqrt {\frac {a}{a+b}+\frac {b \sin (c+d x)}{a+b}}}dx}{\sqrt {a+b \sin (c+d x)}}}{a^2-b^2}+\frac {2 b \left (23 a^2+9 b^2\right ) \cos (c+d x)}{d \left (a^2-b^2\right ) \sqrt {a+b \sin (c+d x)}}}{3 \left (a^2-b^2\right )}+\frac {16 a b \cos (c+d x)}{3 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{3/2}}}{5 \left (a^2-b^2\right )}+\frac {2 b \cos (c+d x)}{5 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{5/2}}\)

\(\Big \downarrow \) 3140

\(\displaystyle \frac {2 b \cos (c+d x)}{5 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{5/2}}+\frac {\frac {16 a b \cos (c+d x)}{3 d \left (a^2-b^2\right ) (a+b \sin (c+d x))^{3/2}}+\frac {\frac {2 b \left (23 a^2+9 b^2\right ) \cos (c+d x)}{d \left (a^2-b^2\right ) \sqrt {a+b \sin (c+d x)}}+\frac {\frac {2 \left (23 a^2+9 b^2\right ) \sqrt {a+b \sin (c+d x)} E\left (\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )|\frac {2 b}{a+b}\right )}{d \sqrt {\frac {a+b \sin (c+d x)}{a+b}}}-\frac {16 a \left (a^2-b^2\right ) \sqrt {\frac {a+b \sin (c+d x)}{a+b}} \operatorname {EllipticF}\left (\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right ),\frac {2 b}{a+b}\right )}{d \sqrt {a+b \sin (c+d x)}}}{a^2-b^2}}{3 \left (a^2-b^2\right )}}{5 \left (a^2-b^2\right )}\)

input
Int[(a + b*Sin[c + d*x])^(-7/2),x]
 
output
(2*b*Cos[c + d*x])/(5*(a^2 - b^2)*d*(a + b*Sin[c + d*x])^(5/2)) + ((16*a*b 
*Cos[c + d*x])/(3*(a^2 - b^2)*d*(a + b*Sin[c + d*x])^(3/2)) + ((2*b*(23*a^ 
2 + 9*b^2)*Cos[c + d*x])/((a^2 - b^2)*d*Sqrt[a + b*Sin[c + d*x]]) + ((2*(2 
3*a^2 + 9*b^2)*EllipticE[(c - Pi/2 + d*x)/2, (2*b)/(a + b)]*Sqrt[a + b*Sin 
[c + d*x]])/(d*Sqrt[(a + b*Sin[c + d*x])/(a + b)]) - (16*a*(a^2 - b^2)*Ell 
ipticF[(c - Pi/2 + d*x)/2, (2*b)/(a + b)]*Sqrt[(a + b*Sin[c + d*x])/(a + b 
)])/(d*Sqrt[a + b*Sin[c + d*x]]))/(a^2 - b^2))/(3*(a^2 - b^2)))/(5*(a^2 - 
b^2))
 

3.1.57.3.1 Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3132
Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[2*(Sqrt[a 
 + b]/d)*EllipticE[(1/2)*(c - Pi/2 + d*x), 2*(b/(a + b))], x] /; FreeQ[{a, 
b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]
 

rule 3134
Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[Sqrt[a + 
b*Sin[c + d*x]]/Sqrt[(a + b*Sin[c + d*x])/(a + b)]   Int[Sqrt[a/(a + b) + ( 
b/(a + b))*Sin[c + d*x]], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2 
, 0] &&  !GtQ[a + b, 0]
 

rule 3140
Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/(d*S 
qrt[a + b]))*EllipticF[(1/2)*(c - Pi/2 + d*x), 2*(b/(a + b))], x] /; FreeQ[ 
{a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]
 

rule 3142
Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[Sqrt[(a 
 + b*Sin[c + d*x])/(a + b)]/Sqrt[a + b*Sin[c + d*x]]   Int[1/Sqrt[a/(a + b) 
 + (b/(a + b))*Sin[c + d*x]], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - 
 b^2, 0] &&  !GtQ[a + b, 0]
 

rule 3143
Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(-b)*Cos 
[c + d*x]*((a + b*Sin[c + d*x])^(n + 1)/(d*(n + 1)*(a^2 - b^2))), x] + Simp 
[1/((n + 1)*(a^2 - b^2))   Int[(a + b*Sin[c + d*x])^(n + 1)*Simp[a*(n + 1) 
- b*(n + 2)*Sin[c + d*x], x], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - 
 b^2, 0] && LtQ[n, -1] && IntegerQ[2*n]
 

rule 3231
Int[((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)])/Sqrt[(a_) + (b_.)*sin[(e_.) + ( 
f_.)*(x_)]], x_Symbol] :> Simp[(b*c - a*d)/b   Int[1/Sqrt[a + b*Sin[e + f*x 
]], x], x] + Simp[d/b   Int[Sqrt[a + b*Sin[e + f*x]], x], x] /; FreeQ[{a, b 
, c, d, e, f}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 - b^2, 0]
 

rule 3233
Int[((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*sin[(e_.) + 
(f_.)*(x_)]), x_Symbol] :> Simp[(-(b*c - a*d))*Cos[e + f*x]*((a + b*Sin[e + 
 f*x])^(m + 1)/(f*(m + 1)*(a^2 - b^2))), x] + Simp[1/((m + 1)*(a^2 - b^2)) 
  Int[(a + b*Sin[e + f*x])^(m + 1)*Simp[(a*c - b*d)*(m + 1) - (b*c - a*d)*( 
m + 2)*Sin[e + f*x], x], x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c 
- a*d, 0] && NeQ[a^2 - b^2, 0] && LtQ[m, -1] && IntegerQ[2*m]
 
3.1.57.4 Maple [A] (verified)

Time = 0.87 (sec) , antiderivative size = 584, normalized size of antiderivative = 2.00

method result size
default \(\frac {\sqrt {-\left (-b \sin \left (d x +c \right )-a \right ) \left (\cos ^{2}\left (d x +c \right )\right )}\, \left (\frac {2 \sqrt {-\left (-b \sin \left (d x +c \right )-a \right ) \left (\cos ^{2}\left (d x +c \right )\right )}}{5 b^{2} \left (a^{2}-b^{2}\right ) \left (\sin \left (d x +c \right )+\frac {a}{b}\right )^{3}}+\frac {16 a \sqrt {-\left (-b \sin \left (d x +c \right )-a \right ) \left (\cos ^{2}\left (d x +c \right )\right )}}{15 \left (a^{2}-b^{2}\right )^{2} b \left (\sin \left (d x +c \right )+\frac {a}{b}\right )^{2}}+\frac {2 b \left (\cos ^{2}\left (d x +c \right )\right ) \left (23 a^{2}+9 b^{2}\right )}{15 \left (a^{2}-b^{2}\right )^{3} \sqrt {-\left (-b \sin \left (d x +c \right )-a \right ) \left (\cos ^{2}\left (d x +c \right )\right )}}+\frac {2 \left (15 a^{3}+17 a \,b^{2}\right ) \left (\frac {a}{b}-1\right ) \sqrt {\frac {a +b \sin \left (d x +c \right )}{a -b}}\, \sqrt {\frac {b \left (1-\sin \left (d x +c \right )\right )}{a +b}}\, \sqrt {\frac {\left (-1-\sin \left (d x +c \right )\right ) b}{a -b}}\, F\left (\sqrt {\frac {a +b \sin \left (d x +c \right )}{a -b}}, \sqrt {\frac {a -b}{a +b}}\right )}{\left (15 a^{6}-45 a^{4} b^{2}+45 a^{2} b^{4}-15 b^{6}\right ) \sqrt {-\left (-b \sin \left (d x +c \right )-a \right ) \left (\cos ^{2}\left (d x +c \right )\right )}}+\frac {2 b \left (23 a^{2}+9 b^{2}\right ) \left (\frac {a}{b}-1\right ) \sqrt {\frac {a +b \sin \left (d x +c \right )}{a -b}}\, \sqrt {\frac {b \left (1-\sin \left (d x +c \right )\right )}{a +b}}\, \sqrt {\frac {\left (-1-\sin \left (d x +c \right )\right ) b}{a -b}}\, \left (\left (-\frac {a}{b}-1\right ) E\left (\sqrt {\frac {a +b \sin \left (d x +c \right )}{a -b}}, \sqrt {\frac {a -b}{a +b}}\right )+F\left (\sqrt {\frac {a +b \sin \left (d x +c \right )}{a -b}}, \sqrt {\frac {a -b}{a +b}}\right )\right )}{15 \left (a^{2}-b^{2}\right )^{3} \sqrt {-\left (-b \sin \left (d x +c \right )-a \right ) \left (\cos ^{2}\left (d x +c \right )\right )}}\right )}{\cos \left (d x +c \right ) \sqrt {a +b \sin \left (d x +c \right )}\, d}\) \(584\)

input
int(1/(a+b*sin(d*x+c))^(7/2),x,method=_RETURNVERBOSE)
 
output
(-(-b*sin(d*x+c)-a)*cos(d*x+c)^2)^(1/2)*(2/5/b^2/(a^2-b^2)*(-(-b*sin(d*x+c 
)-a)*cos(d*x+c)^2)^(1/2)/(sin(d*x+c)+a/b)^3+16/15*a/(a^2-b^2)^2/b*(-(-b*si 
n(d*x+c)-a)*cos(d*x+c)^2)^(1/2)/(sin(d*x+c)+a/b)^2+2/15*b*cos(d*x+c)^2/(a^ 
2-b^2)^3*(23*a^2+9*b^2)/(-(-b*sin(d*x+c)-a)*cos(d*x+c)^2)^(1/2)+2*(15*a^3+ 
17*a*b^2)/(15*a^6-45*a^4*b^2+45*a^2*b^4-15*b^6)*(a/b-1)*((a+b*sin(d*x+c))/ 
(a-b))^(1/2)*(b*(1-sin(d*x+c))/(a+b))^(1/2)*((-1-sin(d*x+c))*b/(a-b))^(1/2 
)/(-(-b*sin(d*x+c)-a)*cos(d*x+c)^2)^(1/2)*EllipticF(((a+b*sin(d*x+c))/(a-b 
))^(1/2),((a-b)/(a+b))^(1/2))+2/15*b*(23*a^2+9*b^2)/(a^2-b^2)^3*(a/b-1)*(( 
a+b*sin(d*x+c))/(a-b))^(1/2)*(b*(1-sin(d*x+c))/(a+b))^(1/2)*((-1-sin(d*x+c 
))*b/(a-b))^(1/2)/(-(-b*sin(d*x+c)-a)*cos(d*x+c)^2)^(1/2)*((-a/b-1)*Ellipt 
icE(((a+b*sin(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))+EllipticF(((a+b*si 
n(d*x+c))/(a-b))^(1/2),((a-b)/(a+b))^(1/2))))/cos(d*x+c)/(a+b*sin(d*x+c))^ 
(1/2)/d
 
3.1.57.5 Fricas [C] (verification not implemented)

Result contains higher order function than in optimal. Order 9 vs. order 4.

Time = 0.16 (sec) , antiderivative size = 1051, normalized size of antiderivative = 3.60 \[ \int \frac {1}{(a+b \sin (c+d x))^{7/2}} \, dx=\text {Too large to display} \]

input
integrate(1/(a+b*sin(d*x+c))^(7/2),x, algorithm="fricas")
 
output
-1/45*((3*sqrt(2)*(a^4*b^2 - 33*a^2*b^4)*cos(d*x + c)^2 + (sqrt(2)*(a^3*b^ 
3 - 33*a*b^5)*cos(d*x + c)^2 - sqrt(2)*(3*a^5*b - 98*a^3*b^3 - 33*a*b^5))* 
sin(d*x + c) - sqrt(2)*(a^6 - 30*a^4*b^2 - 99*a^2*b^4))*sqrt(I*b)*weierstr 
assPInverse(-4/3*(4*a^2 - 3*b^2)/b^2, -8/27*(8*I*a^3 - 9*I*a*b^2)/b^3, 1/3 
*(3*b*cos(d*x + c) - 3*I*b*sin(d*x + c) - 2*I*a)/b) + (3*sqrt(2)*(a^4*b^2 
- 33*a^2*b^4)*cos(d*x + c)^2 + (sqrt(2)*(a^3*b^3 - 33*a*b^5)*cos(d*x + c)^ 
2 - sqrt(2)*(3*a^5*b - 98*a^3*b^3 - 33*a*b^5))*sin(d*x + c) - sqrt(2)*(a^6 
 - 30*a^4*b^2 - 99*a^2*b^4))*sqrt(-I*b)*weierstrassPInverse(-4/3*(4*a^2 - 
3*b^2)/b^2, -8/27*(-8*I*a^3 + 9*I*a*b^2)/b^3, 1/3*(3*b*cos(d*x + c) + 3*I* 
b*sin(d*x + c) + 2*I*a)/b) - 3*(3*sqrt(2)*(-23*I*a^3*b^3 - 9*I*a*b^5)*cos( 
d*x + c)^2 + (sqrt(2)*(-23*I*a^2*b^4 - 9*I*b^6)*cos(d*x + c)^2 + sqrt(2)*( 
69*I*a^4*b^2 + 50*I*a^2*b^4 + 9*I*b^6))*sin(d*x + c) + sqrt(2)*(23*I*a^5*b 
 + 78*I*a^3*b^3 + 27*I*a*b^5))*sqrt(I*b)*weierstrassZeta(-4/3*(4*a^2 - 3*b 
^2)/b^2, -8/27*(8*I*a^3 - 9*I*a*b^2)/b^3, weierstrassPInverse(-4/3*(4*a^2 
- 3*b^2)/b^2, -8/27*(8*I*a^3 - 9*I*a*b^2)/b^3, 1/3*(3*b*cos(d*x + c) - 3*I 
*b*sin(d*x + c) - 2*I*a)/b)) - 3*(3*sqrt(2)*(23*I*a^3*b^3 + 9*I*a*b^5)*cos 
(d*x + c)^2 + (sqrt(2)*(23*I*a^2*b^4 + 9*I*b^6)*cos(d*x + c)^2 + sqrt(2)*( 
-69*I*a^4*b^2 - 50*I*a^2*b^4 - 9*I*b^6))*sin(d*x + c) + sqrt(2)*(-23*I*a^5 
*b - 78*I*a^3*b^3 - 27*I*a*b^5))*sqrt(-I*b)*weierstrassZeta(-4/3*(4*a^2 - 
3*b^2)/b^2, -8/27*(-8*I*a^3 + 9*I*a*b^2)/b^3, weierstrassPInverse(-4/3*...
 
3.1.57.6 Sympy [F]

\[ \int \frac {1}{(a+b \sin (c+d x))^{7/2}} \, dx=\int \frac {1}{\left (a + b \sin {\left (c + d x \right )}\right )^{\frac {7}{2}}}\, dx \]

input
integrate(1/(a+b*sin(d*x+c))**(7/2),x)
 
output
Integral((a + b*sin(c + d*x))**(-7/2), x)
 
3.1.57.7 Maxima [F]

\[ \int \frac {1}{(a+b \sin (c+d x))^{7/2}} \, dx=\int { \frac {1}{{\left (b \sin \left (d x + c\right ) + a\right )}^{\frac {7}{2}}} \,d x } \]

input
integrate(1/(a+b*sin(d*x+c))^(7/2),x, algorithm="maxima")
 
output
integrate((b*sin(d*x + c) + a)^(-7/2), x)
 
3.1.57.8 Giac [F]

\[ \int \frac {1}{(a+b \sin (c+d x))^{7/2}} \, dx=\int { \frac {1}{{\left (b \sin \left (d x + c\right ) + a\right )}^{\frac {7}{2}}} \,d x } \]

input
integrate(1/(a+b*sin(d*x+c))^(7/2),x, algorithm="giac")
 
output
integrate((b*sin(d*x + c) + a)^(-7/2), x)
 
3.1.57.9 Mupad [F(-1)]

Timed out. \[ \int \frac {1}{(a+b \sin (c+d x))^{7/2}} \, dx=\int \frac {1}{{\left (a+b\,\sin \left (c+d\,x\right )\right )}^{7/2}} \,d x \]

input
int(1/(a + b*sin(c + d*x))^(7/2),x)
 
output
int(1/(a + b*sin(c + d*x))^(7/2), x)